Question

A monkey of mass `20kg` is holding a vertical rope. The rope will not break when a mass of `25kg` is suspended from it but will break it the mass exeeds `25kg` . What is the maximum acceleration with which the monkey can climb up along the rope? `(g=10m//s^(2))` .
A. `5 m//s^2`
B. `10 m//s^2`
C. `25 m//s^2`
D. `2.5 m//s^2`

Answer 1

Correct Answer - D
`T_"max"`=25 g , ma=`T_"max"`-mg
`rArr a=g/4=10/4=2.5 m//s^2`