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The Gibbs energy for the decomposition of `Al_(2)O_(3)` at `500^(@)C` is as follow :
`(2)/(3)Al_(2)O_(3) rarr (4)/(3)Al+O_(2), Delta_(r)G= +960 kJ mol^(-1)`
The potential difference needed for the electrolytic reduction of aluminium oxide `(Al_(2)O_(3))` at `500^(@)C` is
A. 3.0 V
B. 2.5 V
C. 5.0 V
D. 4.5 V

1 Answer

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Best answer
Correct Answer - B
`DeltaG^(@)=-nFE^(@)`
`960xx100=-4xx96500xxE^(@)`
`E^(@)=-2.48V`
So difference = 2.5 V

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