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A certain gas takes three times as long to effuse out as helium. Its molar mass will be

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A certain gas takes three times as long to effuse out as helium. Its molar mass will be
A. 36 u
B. 64 u
C. 9 u
D. 27 u
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1 Answer

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Correct Answer - A
`(r_(1))/(r_(2))=sqrt((M_(w_(2)))/(M_(w_(1))))`
`(V_(1))/(t_(1))xx(t_(2))/(V_(2))=sqrt((M_(w_(2)))/(M_(w_(a))))`
volume is same
`(3)/(1)=sqrt((M_(w_(2)))/(4))`
`9=(M_(w_(2)))/(4)" "therefore M_(w_(2))=36`
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