Correct Answer - `0.331g,2.80xx10^(21)`molecule
`Q=900C`
`2Cl^(-)toCl_(2)+2e^(-)," "2xx96500" C liberate "Cl_(2)=1`mole
`therefore900C` will liberate `Cl_(2)=(1)/(2xx96500)xx900=4.66xx10^(-3)"mole"=(4.66xx10^(-3))xx71g=0.331g`
`=(4.66xx10^(-3))xx6.02xx10^(23)` molecules `=2.80xx10^(21)` molecules.