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Find out the molar conductivity of an aqueous solution of `BaCl_(2)` at infinite dilution when ionic conductances of `Ba^(2+)` and `Cl^(-)` ion are 127.30 S `cm^(2)mol^(-1)` and 76.34 S `cm^(2)mol^(-1)` respectively.

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Correct Answer - `279.99" S "cm^(2)mol^(-1)`
`wedge_(m)^(@)(BaCl_(2))=lamda_(Ba^(2+))^(@)+2lamda_(Cl^(-))^(@)=127.30+2(76.34)" S "cm^(2)mol^(-1)=279.99" S "cm^(2)mol^(-1)`

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