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At 291K, saturated solution of `BaSO_(4)` was found to have a specific conductivity of 3.648`xx10^(-6)ohm^(-1)cm^(-1)`, that of water used being `1.25xx10^(-6)ohm^(-1)cm^(-1)`. Ioinc conductances of `Ba^(2+) and SO_(4)^(2-)` ions are 110 and 136.6 `ohm^(-1)cm^(2)mol^(-1)` respectively. calculate the solubility of `BaSO_(4)` at 291 K. (At masses: `Ba=137,S=32,O=16)`

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Correct Answer - `2.266xx10^(-3)gL^(-1)`
`kappa(BaSO_(4))=kappa("solution")-kappa("water")." solubility"=(kappaxx1000)/(wedge_(m)^(@))=((3.648-1.250)10^(-6)xx1000)/((110+136.6))xx233" g "L^(-1)`.

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