Question

A copper wire is dipped in `AgNO_(3)` solution kept in beaker A and a silver wire is dipped in a solution of copper suphate kept in beaker B. if standard electrode potential for
`Cu^(2+)+2e^(-)toCu` is +0.34 V and for `Ag^(+)+e^(-)toAg` is +0.80V,
predit in which beeaker the ions present will get reduced?

Answer 1

The probable reaction in beaker A will be
`Cu+2AgNO_(3)toCu(NO_(3))_(2)+2Ag, i.e., Cu+2Ag^(+)toCu^(2+)+2Ag`
`E_(cell)` for this reaction `=-0.34+0.80=+0.46V` i.e., it is +ve. Hence, `Ag^(+)` ions are reduced to Ag.