Question

Calculate the emf of the following cell at 298K
`Fe_((s))|Fe^(2+)(0.001M)||H^(+)(1M)|H_(2(g))(1" bar"),Pt_((s))` (Given `E_(cell)^(@)=+0.44V`)

Answer 1

Correct Answer - 0.53 V
`Fe+2H^(+)toFe^(2+)+H_(2)`,
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Fe^(2+)])/([H^(+)]^(2))=0.44-(0.0591)/(2)"log"(0.001)/((1)^(2))`