Correct Answer - B
`2Cl^(-)toCl_(2)(g)+2e^(-)`
To produce 1 mol of `Cl_(2)`, charge required
`=2F=2xx96500C`
`therefore`To produce 0.1 mol of `Cl_(2)`, charge required
`=2xx96500xx0.1=19300C`
`Q=Ixxt`
`thereforet=Q=(19300)/(3)sec=(19300)/(3xx60)`min
`=107.22"min"cong110`min