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In a cell that utilizes the reaction `Zn(s)+2H^(+)(aq)toZn^(2+)(aq)+H_(2)(g)` addition of `H_(2)SO_(4)` to the cathode compartment will
A. Lower the E and shift equilibrium to the left
B. lower the E and shift equilibrium to the right
C. increase the E and shift equilibrium to the right
D. Increase the E and shift equilibrium to the left

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Correct Answer - C
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Zn^(2+)]xxp_(H_(2)))/([H^(+)]^(2))`
On adding `H_(2)SO_(4),[H^(+)]` will increase, therefore `E_(cell)` will increase. The equilibrium `Zn+2H^(+)hArrZn^(2+)+H_(2)` will shift towards right on increasing the concentration of `H^(+)` ions.

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