Question

Mole fraction of urea in its aqueous solution is 0.2, them molality of the solution will be.

Answer 1

`m=(x_(A))/(x_(B))=(1000)/(M_(B))` where, `x_(A)` - solute, `x_(B)` - solvent
`m=(0.2)/(0.8)xx(1000)/(18)=(250)/(18)=13.8` .