Question

Power dissipated across the `8 Omega` in the circuit shown here is `2 W`. The power dissiated in watt units across the `3 Omega` is

A. `2.0`
B. `1.0`
C. `0.5`
D. `3.0`

Answer 1

Correct Answer - D
As voltage drop across
`8Omega=sqrt(2xx8)=4V(thereforep=V^(2)/(R))`
Therefore voltage drop across`3Omega=3v`
[`therefore`4V is divided in ration of resistances between `1Omega and 3Omega`]
Hence power dissipated in `3Omega=(3)^(2)/(3)=3"watt"`