Question

Calculate the degree of hydrolysis of 0.1 M solution of sodium acetate at `298 K : K_(a) = 1.8 xx 10^(-5)`.

Answer 1

Hydrolysis constant `(K_(n))=(K_(w))/(K_(a))=(1xx10^(-14))/(1.8xx10^(-5))=5.5xx10^(-10)`
Degree of hydrolysis `(h)=sqrt((K_(h))/(c))=sqrt((5.5xx10^(-10))/(0.1))=(55xx10^(-10))^(1//2)=7.42xx10^(-5)`