Question

An aqueous solution of glucose is made by dissolving 10 g of glucose in 90 g water at 303 K. If the V.P. of pure water at 303 K be 32.8 mm Hg, what would be V.P. fo the solution ?

Answer 1

`(32.8-P_(s))/(32.8)=((10)/(60))/((10)/(60)+(90)/(18))`
`(32.8-P_(s))/(32.8)=(0.16)/(0.16+5)`
`(32.8-P_(s))/(32.8)=0.03`
`32.8-P_(s)=1.017`
`P_(s)=31.7" atm"`

Comments

Why r u taking molecular weight of glucose as 60??????????? molecular weight of glucose is 180