i. (3x + 2x^2 + 4x^3) ÷ (x – 4) ii. (2m^3 + m^2 + m + 9) ÷ (2m – 1)

Question

Divide and write the quotient and the remainder.

i. (3x + 2x² + 4x³) ÷ (x – 4) 

ii. (2m³ + m² + m + 9) ÷ (2m – 1)

Answer 1

i. (3x + 2x² + 4x³) ÷ (x – 4) 

Write the dividend in descending order of their indices.

3x + 2x² + 4x³ = 4x³ + 2x² + 3x

∴ Quotient = 4x² + 18x + 75 

Remainder = 300

ii. (2m³ + m² + m + 9) ÷ (2m – 1)

∴ Quotient = m² + m + 1 

Remainder = 10