Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
441 views
in Physics by (38.3k points)
closed by

If the mass of a planet is eight times the mass of the earth and its radius is twice the radius of the earth, what will be the escape velocity for that planet?

1 Answer

+1 vote
by (40.5k points)
selected by
 
Best answer

Given:

(1) The mass of the planet (M) is eight times the mass of the earth, i.e., 8 × 6 × 1024 kg

(2) The radius of the planet (R) is twice the radius of the earth, i.e., 2 × 6.4 × 106 km

(3) G = 6.67 × 10-11 N·m2/kg2

Escape velocity for that planet

= 2.237 × 104 m/s

= 22.37 km/s

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...