Question

Find the HCF

i. 25, 40 

ii. 56, 32 

iii. 40, 60, 75 

iv. 16, 27 

v. 18, 32, 48

Answer 1

i. 25, 40

∴ 25 = 5 × 5 

40 = 2 × 2 × 2 × 5 

∴ HCF of 25 and 40 = 5

ii. 56, 32

∴ 56 = 2 × 2 × 2 × 7 

32 = 2 × 2 × 2 × 2 × 2 

∴ HCF of 56 and 32 = 2 × 2 × 2 

∴ HCF of 56 and 32 = 8

iii. 40, 60, 75

∴ 40 = 2 × 2 × 2 × 5 

60 = 2 × 2 × 3 × 5 

75 = 3 × 5 × 5 

∴ HCF of 40, 60 and 75 = 5

iv. 16, 27

∴ 16 = 2 × 2 × 2 × 2 × 1 

27 = 3 × 3 × 3 × 1 

∴ HCF of 16 and 27 = 1

v. 18, 32,48

∴ 18 = 2 × 3 × 3 

32 = 2 × 2 × 2 × 2 × 2 

48 = 2 × 2 × 2 × 2 × 3 

∴ HCF of 18, 32 and 48 = 2