Total charge on all three capacitors =`40muC`
Total capacity `(1+2+32)muF=6muF`
a. common potential
`V=("Total charge")/("Total capacity")`
`=(40muC)/(6muF)=20/3vol t`
b. `q_1C_1V=(1muF)(20/3)=20/3muC`
`q_2=C_2V=(2muF)(20/3)=40/3muC`
`q_3=C_3V=(3muF)(20/3)=20muC`