Correct Answer - A::C
a. Let `q` be the charge on smaller sphere. Then
`V_("inner")=0`
`:. (Kq)/2+(K(2))/4=0` or `q=-1muC`
Now, `V_(outer)=(K(2-1)xx10^-6)/(4xx10^-2)`
`(9xx10^9xx10^-6)/(4xx10^-2)`
`=2.25xx10^5V`
b. charge distribution is as shown in above figure.