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A square loop of side a carris a current `I`. The magnetic field at the centre of the loop is
A. `(2mu_0Isqrt2)/(pia)`
B. `(mu_0Isqrt2)/(pia)`
C. `(4mu_0Isqrt2)/(pia)`
D. `(mu_0I)/(pia)`

1 Answer

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Best answer
Correct Answer - A
image
`B_C=3[mu_0/(4pi) I/(a/2)(sin45^@+sin45^@)]`
`(2sqrt2m_0I)/(pia)`

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