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A charged particle moving along +ve x-direction with a velocity v enters a region where there is a uniform magnetic field `B_0(-hat k), from x=0 to x=d.` The particle gets deflected at an angle `theta` from its initial path. The specific charge of the particle is
image
A. `(Bd)/(vcostheta)`
B. `(vtantheta)/(Bd)`
C. (Bsintheta)/(vd)`
D. `(vsintheta)/(Bd)`

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Best answer
Correct Answer - D
image
`sintheta=d/r=d/((mv/Bq))=q/m=(vsintheta)/(Bd)`

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