Correct Answer - A::C
`B_1=(mu_0N_1iI_1)/(2R_1)`
`=((4pixx10^I-7)(50)(2))/(2(5xx10^-2))`
`=4pixx10^-4T`
`B_2=(mu_0N_2i_2)/(2R_2)`
`=((4pixx10^-7)(100)(2))/((2)(10xx10^-2))`
`=4pixx10^-4T`
When currets are in the same direction then
`B_("net")=B_1+B_2`
When curents are in the opposite direction, then
`B_("net")=B_1-B_2`