Question

A charged particle of unit mass and unit charge moves with velocity `vecv=(8hati+6hatj)ms^-1` in magnetic field of `vecB=2hatkT`. Choose the correct alternative (s).
A. The path of the particle may be `x^2+y^2-4x-21=0`
B. The path of the particle may be `x^2+y^2=25`
C. The path of the particle may be `y^2+z^2=25`
D. The time period of the particle will be 3.14 s

Answer 1

Correct Answer - A::B::D
`r=(mV)/(Bq)=((1)(10))/((2)(1))=5m`
`T=(2pim)/(Bq)=((2)(pi)(1))/((2)(1))=pi`
`=3.14s`
Plane of circle is perpendicular to `B`, i.e., `xy`-plane.