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A particle of mass `m` having a charge q enters into a circular region of radius `R` with velocity `v` directed towards the centre. The strength of ma

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A particle of mass `m` having a charge q enters into a circular region of radius `R` with velocity `v` directed towards the centre. The strength of magnetic field is `B`. Find the deviation in the path of the particle.
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`theta=tan^-1 (R/r) =tan^-1(R/(mv/Bq))=tan^-1((BqR)/(mv))`
Deviation `=2theta=2tan^-1((BqR)/(mv))`
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