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The current (in Ampere) in an inductor is given by `l=5+16t`, where `t` in seconds. The selft - induced emf in it is `10mV`. Find
(a) the self-inductance, and
(b) the energy stored in the inductor and the power supplied to it at `t =1s`

1 Answer

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a. `dI//dt=16A//s`
`:.L=|e/(dI//dt)|=(10xx10^-3)/16`
`=0.625xx10^-3H=0.625mH`
b. At `t=1s, I=21A`
`U=1/2LI^2=1/2xx(0.625xx10^-3)(21)^2`
`=0.137J`
`P=Ei=(10xx10^-3)(21)`
`=0.21J//s`

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