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The armature of a `DC` motor has `20Omega` resistance. It draws a current of `1.5 A` when run by `200 V DC` supply The value of back emf induced in it will be
A. `150V`
B. `170V`
C. `180V`
D. `190V`

1 Answer

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Best answer
Correct Answer - B
Back emf = Applied voltage potential drop across armature coil
`=200-iR`
`=200-1.5xx20`
`=170V`

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