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+1 vote
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in Physics by (93.6k points)
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10 ओम प्रतिरोध तथा 10 हेनरी प्रेरकत्व की एक कुण्डली 50 वोल्ट की बैटरी से जोड़ी गयी है । कुण्डली में संचित ऊर्जा है ।
A. `125` जूल
B. `62.5` जूल
C. `250` जूल
D. `500` जूल

2 Answers

+2 votes
by (36.2k points)
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Best answer

सही विकल्प है (A) 125 जूल

कुण्डली का प्रतिरोध, R = 10 ओम

कुण्डली का प्रेरकत्व, L = 10 H

बैटरी का वोल्टेज, V = 50 वोल्ट

ओम के नियम के अनुसार:

\(V = IR\)

\(I = \frac VR\)

\(I = \frac{50}{10} = 5A\)

कुण्डली में संचित ऊर्जा,

U = \(\frac 12 LI^2\)

\(= \frac 12 \times 10 \times(5)^2\)

\(= \frac{250}2\)

\(= 125\) J

+1 vote
by (91.2k points)
Correct Answer - A
ऊर्जा `= 1/2 Li_(0)^(2), i_(0) = 5 "ऐम्पियर"`

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