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`5000 Å`तरंगदैर्घ्य वाले एकवर्णीय प्रकाश के फोटॉन की ऊर्जा ज्ञात कीजिए |
(`h=6.6xx10^(-34) ` जूल-सेकण्ड, `c=3.0xx10^(8)` मीटर/सेकण्ड )।

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v आवृत्ति के फोटॉन की hv ऊर्जा होती है । परन्तु `v= c//lambda`, जहाँ c प्रकाश कि चाल है तथा `lambda` फोटॉन की तरंगदैर्घ्य है । अतः फोटॉन कि ऊर्जा
`E=(hc)/(lambda)=((6.6xx10^(-34)" जूल-सेकण्ड")xx(3.0xx10^(8)" मीटर /सेकण्ड"))/(5000xx10^(-10)" मीटर")`
`=3.96xx10^(-19)` जूल ।

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