Question

In a series `C-R` circuit shown in figureure, the applied voltage is `10 V` and the voltage across capacitor is found to`8 V`. The voltage across `R`, and the phase difference between current and the applied voltage will respectively be
.
A. `6V, tan^-1(4/3)`
B. `3V,tan^-1(3/4)`
C. `6V,tan^-1(3/4)`
D. none of these

Answer 1

Correct Answer - A
`V_R=sqrt(V^2-V_C^2)=sqrt((10)^2-(8)^2)=6V`
`tanphi=X_C/X_R=V_C/V_R=8/6=4/3`