Question

A glass sphere has radius of `5.0 cm` and a refractive index of `1.6.` A paperweight is constructed by slicing through the sphere on a plate that is `2.0 cm` from the centre of the sphere and perpendicular to radius of the sphere that passes through the centre of the circle formed by the intersection of the plane and the sphere. The paperweight is placed on a table and viewed from directly above an observer who is `8.0 cm` from the table top, as shown in figure. When viewed through the paperweight, how far away does the table top appear to the observer?

Answer 1

Correct Answer - B::C::D
Applying `mu_2/v=mu_1/u=(mu_2-mu_1)/R` we have,

`1.0/v-1.6/(-3.0)=(1.0-1.6)/(-5.0)`
Solving we get, `v=-2.42 cm`
This is distance from P (downwards).
`:.` Distance from observer `=5+2.42`
`=7.42 cm`