Question

The potential difference applied to an X-ray tube is 5k V and the current through it is 3.2 mA. Then, the number of electrons striking the target per second is. (a) `2xx10^16` (b) `5xx10^6` (c ) `1xx10^17` (d) `4xx10^15`.

Answer 1

Correct Answer - A::B
`:. i= (q)/(t) = (ne)/(t)`
`:. N = (I t)/(e )`
Substituting `I = 3.2xx10^(-3) A,`
`e=1.6xx10^(-19) C and t = 1s`
We get, n = 2xx10^16`
:. The correct answer is (a) .