Question

Find the energy and mometum of a photon of ultraviolet radiation of 280 nm wavelength.

Answer 1

\(E = \frac {hc}\lambda\)

\(= \frac{6.63 \times 10^{-34}\times 3 \times 10^8}{280 \times 10^{-9}}\)

\(= 0.0710 \times 10^{-17}\)

\(E = 7.10 \times 10^{-19}\) J