Correct Answer - B
The series in U-V region is Lyman series. Largest
wavelength correspond to minimum energy which
occurs in transition from n= to n=1.
`:. 122 = ((1)/(R))/(((1)/(1^2)-(1)/(2^2))) ....(i)`
The smallest wavelength in the infrared region
corresponds to maximum energy of Paschen series.
`122 = ((1)/(R))/(((1)/(1^2)-(1)/(2^2))) ....(i)`
The smallest wavelength in the infrared region
corresponds to maximum energy of Paschen series.
`:. ((1)/(R))/(((1)/(3^2)-(1)/(oo) .....(ii)`
Solving Eqs. (i) and (ii) we get
`lambda = 823.5 nm`
`:.` Correct option in (b).