Correct Answer - A
`K = (P^2) /(2m)`
in collision, momentum p remains constant.
`:. K prop (1)/(mass)`
After collision, mass has doubled. So kinetic
energy will remain `(K)/(2).` Hence,loss is also `(K)/(2)`
Now, `(K)/(2)` = minimum excitation energy required.
=10.2 eV
`rArr K = 20.4 eV`