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The half-life of `_92^238U` against alpha decay is `4.5xx10^9` year. How much disintegration per second occurs in 1 g of `_92^238U`?

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The half-life of `_92^238U` against alpha decay is `4.5xx10^9` year. How much disintegration per second occurs in 1 g of `_92^238U`?
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Correct Answer - A::B::C::D
`R=lambdaN=((1n2)/(t_(1//2)))N`
`=(0.693)/(4.5xx10^9xx365xx24xx3600)((1)/(238))(6.02xx10^23)`
`=1.23xx10^4dps`
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