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If `R` is the radius of the octahedral voids and `r` is the radius of the atom in close packing, then `r//R` is equal to
A. `2.41`
B. `4.76`
C. `3.22`
D. `9.1`

1 Answer

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Best answer
Correct Answer - A
For `OV`,
`R/r` (i.e., `(r_(o+))/(r_(ɵ))` or `(r_("void"))/(r_(ɵ))`) `= 0.414`
`:. (r)/(R) = (1)/(0.414) = 2.41`

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