Question

In a crystallizes solid, anions `B` are arranged in cubic close packing, cations `A` are equally distributed between octahedral and tetrahedral voids, what is the formula of the solid?

Answer 1

Correct Answer - A_(2)B`
Let number of anion `B^(ɵ) = 1//"atom"`
Number of `TV = 2//"atom"`
Number of `OV = 1//"atom"`
`2 TV_(s)` are present above and below each sphere and I `OV` per atom is present in midway between the two close-packed layers).
Number of cation `A^(o+) = 2`
(Since cation `A` is equally distributed between `OV` and `TV`).
Formula: `A_(2)B`