Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
71 views
in Chemistry by (92.0k points)
closed by
In order to completely oxidize `0.1 mol` of `MnO_(4)^(2-)` to permanganate ion. The quantity of electricity required is
A. `96500C`
B. `2xx96500C`
C. `9650C`
D. `96.50C`

1 Answer

0 votes
by (92.8k points)
selected by
 
Best answer
Correct Answer - c
`MnO_(4)^(2-)rarr MnO_(4)^(c-)+e^(-)`
`1F=1mol `of `MnO_(4)^(c-)`
` 0.1F=0.1 mol` of `MnO_(4)^(c-)`
`0.1F=0.1xx96500=9650C`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...