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Select the correct statement.
A. Faraday represents `96500` coulombs per second.
B. Coulomb represents one ampere for `1//2` second.
C. Coulomb represents `1//2` ampere for 1 second
D. Coulomb represnts charge of one mole electrone.

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Correct Answer - d
`F=N_(A)XX` charge of `e^(-)`
`96500C=6.023xx10^(23)xx` Charge of `e^(-)`
`:.` Charge`=(96500)/(6.023xx10^(23))=1.602xx10^(-19)C`

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