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`13g` of metal `M` is deposited at cathode by passing `0.4F` of electricity . The cathodic reaction is `:`
`M^(n+)+n e^(-) rarr M`
The formula of metal chloride `(Aw=65)` is `……………………..` .

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Correct Answer - `(MCl_(2))`
`(MCl_(2))`
`0.4F=0.4Eq of M=(13.0g)/(Ew)`
`:. Ew=32.5`
Valency `=(Aw)/(Ew)=(65)/(32.5)=2`
Formula `=MCl_(2)`

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