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The standard potential of `Cl^(c-)|AgCl|Ag` half cell is related to that of `Ag^(o+)|Ag` though the expression.
`E^(c-)._(Ag^(o+)|Ag)=E^(c-)._(Cl^(c-)|AgCl|A)+(RT)/(F)ln K_(sp)(AgCl)`

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Best answer
Correct Answer - F
The current expression is
`E^(c-)._(Cl^(c-)|AgCl|Ag)=E^(c-)._(Ag^(o+)|Ag)+(RT)/(F)ln K_(sp)(AgCl)`

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