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For the reaction
`H_(2) (g)+I_(2)(g) rarr 2HI(g)`, the rate of disappearance of `HI` will be `1.0 xx 10^(-4) mol L^(-1) s^(-1)`. The rate of appearance of `HI` will be
A. `1.0 xx 10^(-4) mol L^(-1) s^(-1)`
B. `2.0 xx 10^(-4) mol L^(-1) s^(-1)`
C. `0.50 xx 10^(-4) mol L^(-1) s^(-1)`
D. `4.0 xx 10^(-4) mol L^(-1) s^(-1)`

1 Answer

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Best answer
Correct Answer - B
`H_(2) (g) + I_(2)(g) rarr 2HI(aq)`
Rate `= (1)/(1)(-d[H_(2)])/(d t) = (1)/(1)(-d[I_(2)])/( d t) = (1)/(2) (+d[HI])/(d t)`
Now, `(d[H_(2)])/(d t) = - 10^(-4) mol L^(-1) s^(-1)`
`:. (d[I_(2)])/(d t) = 2 xx 10^(-4) mol L^(-1) s^(-1)`

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