Question

Following is the graph between `log T_(50)` and `log a` (`a =` initial concentration) for a given reaction at `27^(@)C`. Hence order is

A. `0`
B. `1`
C. `2`
D. `3`

Answer 1

Correct Answer - A
`t_(1//2)prop((1)/(a))^(n-1) or t_(1//2)=k(a)^(1-n)`
`log.t_(1//2)=logk+(1-n)log a (y=c+mx)`
Slope `=(1-n)=tan 45=1`
`:. (1-n)=1impliesn=0`