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in Chemistry by (92.0k points)
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For a chemical reaction `A rarr B`, it is found that the rate of reaction doubles when the concentration of `A` is increased `4` times. What is the order of reaction ? Suggest the rate law also.
A. `4`
B. `0`
C. `1//2`
D. `1`

2 Answers

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by (92.8k points)
 
Best answer
Correct Answer - C
`r_(1) = k[A]^(n)` …(i)
`r_(2)=2r_(1) = k[4A]^(n)` …(ii)
Divide Eq. (ii) by, Eq. (i),
`(2)^(1) = (4)^(n) = (2)^(2n)`
`:. 2n = 1`
`n = (1)/(2)`
0 votes
by (92.8k points)
Correct Answer - C
`r_(1) = k[A]^(n)` …(i)
`r_(2)=2r_(1) = k[4A]^(n)` …(ii)
Divide Eq. (ii) by, Eq. (i),
`(2)^(1) = (4)^(n) = (2)^(2n)`
`:. 2n = 1`
`n = (1)/(2)`

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