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in Chemistry by (92.0k points)
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The rate constant for the reaction
`2N_(2)O_(5) rarr 4NO_(2)+O_(2)`
is `3.0 xx 10^(-5) s^(-1)`. If the rate is `2.40 xx 10^(-5) mol L^(-1) s^(-1)`, then the concentration of `N_(2)O_(5)` (in `mol L^(-1)`) is
A. `1.4`
B. `1.2`
C. `0.04`
D. `0.8`

2 Answers

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by (92.8k points)
 
Best answer
Correct Answer - D
`2N_(2)O_(5)(g) rarr 4NO_(2)(g) + O_(2)(g)`
This reaction is a first order reaction.
Rate `= k[N_(2)O_(5)]`
`2.40 xx 10^(-5) = 3.0 xx 10^(-5) xx[N_(2)O_(5)]`
or `[N_(2)O_(5)] = 0.8 mol L^(-1)`
0 votes
by (92.8k points)
Correct Answer - D
`2N_(2)O_(5)(g) rarr 4NO_(2)(g) + O_(2)(g)`
This reaction is a first order reaction.
Rate `= k[N_(2)O_(5)]`
`2.40 xx 10^(-5) = 3.0 xx 10^(-5) xx[N_(2)O_(5)]`
or `[N_(2)O_(5)] = 0.8 mol L^(-1)`

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