Question

Find the angle of minimum deviation for an equilateral prism made of a material of refractive index 1-732. What is the angle of incidence for this deviation ?

Answer 1

`mu=(sin[(del_(min)+A)/2])/(sin[A/2])A=60^@`
`rarr sqrt3xxsin(30^@)-sin((delta_(min)+60^@)/2)`
`rarr `sqrt3/2=sin((delta_(min)+60^@)/2)`
`rarr ((delta_(min)+60^@)/2)=60^@`
`delta-(min=60^@`
`delta_(min)=2i-A`
`2i=120^@`
`i=60^@`