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A diverging lens of focal length 20 cm and a converging lens of focal length 30 cm are placed 15 cm apart with their principal axes coinciding. Where should an object be placed on the principal axis so that its image formed at infinity ?

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Correct Answer - A::B::C::D
Given that:
`f_1=` focal length of converging lens =30 cm`
f_2=` focal length of diverging lens =20 cm
and d= distance between them =15 cm
Let, F=equivalent focal length
so, `1/F=1/f_1+1/f_2-d/(f_1f_2)`
`=1/30+(1/50)-(5/(30(-20)))`
`=1/1.20`
`rarr F=120cm
rarrThe equivalent lens is a converging one. Distance from diverging lens so that emergent beam is parallel (image at infinity)
`d_1=(dF)/f_1=(15xx120)/30=60cm`
It should be placed 60 cm left to diverging lens. Object should be placed ltbr. `(120-60)=60cm`
from diverging length
similarly `d_2=(dF)/2=(15xx120)/20`
`=90 cm `
`so it should be placed (120+90)lcm`
`=210 cm right to converging lens.

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