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In a Michelson experiment for measuring speed of light, the distance travelled by light between two reflections from the rotating mirror is 4.8 km. The rotating mirror has a shape of a regular octagon. At what minimum angular speed of the mirror (other than zero) the image is formed at the position where a nonrotating mirror forms it ?

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Correct Answer - A::C
In the given Michelson experiment
`D=4.8km=4.8xx10^3m`
We know `c=D(omegan)/(2pi)`
`rarr w=(2pic)/(DN) rad/sec`
`=c/(DN) rev/sec` ltbr. `=(3xx10^8)/((4.8xx10^3xx8)`
`=(7.8)xx10^3 rev/sec`

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