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In an adsorption experiment, a graph between log `(x/m)` versus log `P` was found to be linear with a slope of `45^(@)` . The intercept on the log y axis was found to be `0.301` . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of `3.0` atm.
A. 4
B. 2
C. 6
D. 8

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Best answer
Correct Answer - C
log `(x)/(m)=logK+(1)/(n)logP`
`:.` Plot of log `(x)/(m)` versus log `P` is linear with slope `=(1)/(n)`
and intercept `=logK`
Thus `(1)/(n)=tantheta=tan45^(@)=1` or `n=1`
log `K=0.301` or `K=` antilog `0.301=2`
At `P=3atm`
`(x)/(m)=KP^(1//n)=2xx(3)^(t)=6`

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