Question

As per Bohr model , the minimum energy (in eV) required to remove electron from the ground state of daubly joinized `Li` alon `(Z = 3)` is
A. `1.51`
B. `13.6`
C. `40.8`
D. `122.4`

Answer 1

Correct Answer - D
KEY CONCEPT :
`E_(n) = -13.6((Z^(2)))/((n^(2))) eV`
Therefore , ground state energy of ionized lithium atom `(Z = 3 , n = 1)` will be
`E_(1) = (-13.6 ((3)^(2))/((1)^(2))- 122.4 eV`
`:.` linozation energy of an ground state of doubly ionized lithium will be `122.4eV`.